Tree

"Tree"

It's funny, 'cause the code branches

Anagram creator / Recursion

Earlier, our teacher chalenged us to write a program that outputs a list of anagrams given an input string. A bit later, he said "On second thought, it might be too hard, considering we haven't learned the skills needed yet."

WELL, I DID IT ANYWAYS.

This program uses some serious recursion to return a list of anagrams. For example, "yes" prints out "yes", "yse", "eys", "esy", "sye", and "sey". If the boolean useAllCharacters is set to false, it will print out the string at each step, meaning it will also print anagrams using only some of the characters. For example, "hi" will print "h", "hi", "i", and "ih".

The recursion function works like this- given a string and a list of characters, it will go through the list and each time, call itself with the original string plus a character from the list and the list of characters without the character added to the string. If the list is empty however, it will simply print the completed string, and end without calling itself. More visually demonstrated-

Rapid Counter app- available here!

Rapid Counter

an Android app by Ché Young

       To test out and better understand the Android app development and submission process, I have created this app, Rapid Counter. It is designed to be an ergonomically and aesthetically pleasing counter, with buttons to subtract as well as add to the count, along with a reset button and sounds.

     I would have this submitted to the Google Play store... except for the fact that the $50 signup fee is too high for me to comfortably pay for the moment. However, you can download it here instead. You will likely need to go into your settings to allow installing apps from non-market sources.

Regardless of whether or not you liked it, feel free to give me feedback!

Any input would be much appreciated.

Pig Latin converter

So I made this pig latin translator in class today. It doesn't handle capitalization or punctuation, but it can handle multiple words at once, separated by spaces.

import javax.swing.JOptionPane;

public class home {

static String[] vowels = {"a", "e", "i", "o", "u", "y"};

public static void main(String[] args) {

String input;

String out;

boolean x = true;

while (x) {

input = JOptionPane.showInputDialog("Words to change?");

if (input.equals("stop")){

x=false;

break;

}

out = "";

for (String ret: input.split(" ")){

int vpos = find(ret);

System.out.println(vpos);

if (vpos > 0) {

out = out + ret.substring(vpos) + ret.substring(0, vpos) + "ay ";

} else {

out = out + ret + "way ";

}

}

JOptionPane.showMessageDialog(null, out);

}

}

public static int find(String inp) {

int pos = -1;

for (String vwl: vowels) {

int vpos = inp.indexOf(vwl);

if ((vpos >= 0) && ((vpos < pos)||(pos==-1)) && (vpos != inp.indexOf("qu")+1)) {

pos=inp.indexOf(vwl);

}

}

return pos;

}

}

Age checker

Tim and I made a java program that checks to see if you're 18 years old or older.

import javax.swing.JOptionPane;
import java.util.Calendar;
import java.text.DateFormat;
import java.text.SimpleDateFormat;

public class home {
public static void main(String[] args) {
int day = 0;
int month = 0;
int year = 0;
boolean workingstr = false;
while (workingstr == false) {
String inputValue = JOptionPane.showInputDialog("Please type in your birthday (mm/dd/yy)");
workingstr=true;
try {
day = Integer.parseInt(inputValue.substring(4,5));
month = Integer.parseInt(inputValue.substring(0,2));
year = Integer.parseInt("19"+inputValue.substring(inputValue.length()-2,inputValue.length()));
} catch (NumberFormatException e) {
workingstr=false;
} catch (StringIndexOutOfBoundsException e) {  
workingstr=false; //This section of the program will repeat if any errors are thrown trying to convert the
}                                      //input string to integers.
}
DateFormat dateFormat = new SimpleDateFormat("dd/MM/yyyy");
Calendar cd = Calendar.getInstance();
int todayDay = Integer.parseInt(dateFormat.format(cd.getTime()).substring(0,2));
int todayMonth = Integer.parseInt(dateFormat.format(cd.getTime()).substring(4,5));
int todayYear = Integer.parseInt(dateFormat.format(cd.getTime()).substring(6,10));

if (day<=todayDay) {
month++;
}
if (month<=todayMonth){
year++;
}
if (year+18<=todayYear) {
System.out.println("You're good.");
} else {
System.out.println("Nope! You're underage.");
}
}
}